RTI Connext Professional, Classic Buffer Overflow, CVE-2025-1253 (Critical)

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How CVE-2025-1253 Works

The vulnerability in RTI Connext Professional (Core Libraries) stems from improper bounds checking when handling input data, leading to a classic buffer overflow. Attackers can exploit this flaw by sending crafted payloads that exceed the allocated buffer size, corrupting adjacent memory structures. This allows arbitrary code execution under the context of the application, potentially compromising the entire system. The affected versions include Connext Professional 7.4.0 to 7.5.0, 7.0.0 to 7.3.0.7, and 4.5 to 6.1.2.23. The CVSS 4.0 score reflects its critical severity due to low attack complexity and high impact on confidentiality, integrity, and availability.

DailyCVE Form

Platform: RTI Connext Professional
Version: 7.4.0-7.5.0, 7.0.0-7.3.0.7, 4.5-6.1.2.23
Vulnerability: Buffer Overflow
Severity: Critical
Date: 06/05/2025

Prediction: Patch expected by 07/15/2025

What Undercode Say:

Exploitation Analysis

  1. Crash Trigger – Sending oversized payloads to vulnerable endpoints.
  2. EIP Control – Overwriting return addresses to redirect execution.
  3. ROP Chains – Crafting payloads for code execution bypassing DEP/ASLR.

Protection Measures

1. Input Validation – Enforce strict bounds checking.

  1. Memory Protections – Enable DEP, ASLR, and stack canaries.

3. Patch Deployment – Apply vendor updates immediately.

Exploit Code Snippet (PoC)

include <stdio.h>
include <string.h>
void vulnerable_function(char input) {
char buffer[bash];
strcpy(buffer, input); // No bounds check
}
int main(int argc, char argv) {
vulnerable_function(argv[bash]);
return 0;
}

Mitigation Commands

Enable ASLR
echo 2 | sudo tee /proc/sys/kernel/randomize_va_space
Check for vulnerable versions
rtiddspro --version | grep -E "7.[0-4]|6.[0-1]|4.5"
Apply workaround (if patch unavailable)
iptables -A INPUT -p tcp --dport 7400 -m length ! --length 0:512 -j DROP

Detection Script

import socket
def check_vulnerability(ip, port):
payload = "A" 1024
try:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((ip, port))
s.send(payload.encode())
response = s.recv(1024)
if not response:
print("[!] Service crashed - possibly vulnerable")
except:
print("[+] Target may be vulnerable")

References

Sources:

Reported By: nvd.nist.gov
Extra Source Hub:
Undercode

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